(x+1)(x+1)=x^2-3

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Solution for (x+1)(x+1)=x^2-3 equation:


Simplifying
(x + 1)(x + 1) = x2 + -3

Reorder the terms:
(1 + x)(x + 1) = x2 + -3

Reorder the terms:
(1 + x)(1 + x) = x2 + -3

Multiply (1 + x) * (1 + x)
(1(1 + x) + x(1 + x)) = x2 + -3
((1 * 1 + x * 1) + x(1 + x)) = x2 + -3
((1 + 1x) + x(1 + x)) = x2 + -3
(1 + 1x + (1 * x + x * x)) = x2 + -3
(1 + 1x + (1x + x2)) = x2 + -3

Combine like terms: 1x + 1x = 2x
(1 + 2x + x2) = x2 + -3

Reorder the terms:
1 + 2x + x2 = -3 + x2

Add '-1x2' to each side of the equation.
1 + 2x + x2 + -1x2 = -3 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
1 + 2x + 0 = -3 + x2 + -1x2
1 + 2x = -3 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
1 + 2x = -3 + 0
1 + 2x = -3

Solving
1 + 2x = -3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2x = -3 + -1

Combine like terms: 1 + -1 = 0
0 + 2x = -3 + -1
2x = -3 + -1

Combine like terms: -3 + -1 = -4
2x = -4

Divide each side by '2'.
x = -2

Simplifying
x = -2

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